Replacement of one group by another by means of initial attack by a lone pair of electrons.
2007-02-10 00:59:52
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answer #1
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answered by Gervald F 7
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Nucleophile Definition
2016-09-30 12:52:51
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answer #2
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answered by ? 4
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a nucleophile is a molecule which attacks on +vely charged atom of a substrate.
substitution rcn in which one atom is replaced by another which iis of the reagent .
when nucleophile replace an atom of a substrate then in such a rcn a -ve charged atom is released and this rcn is called nuclephilic substitution rcn.
eg. CH3Cl + aq KOH ---> CH3OH + Cl negative
here the nucleophile is OH negative
THIS RCN IS NUCLEOPHILIC SUBSTITUTION .
2007-02-10 01:20:53
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answer #3
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answered by abhi19 1
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There is a substition on the most postive part of the molecule. A nucleophile will seek out the positive center, bond with it and then the part that was previosly bonded to that positive center will be released.
2007-02-10 01:06:41
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answer #4
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answered by Johnny Z 2
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For the best answers, search on this site https://shorturl.im/aylUp
In chemistry, an electrophile (literally electron-lover) is a reagent attracted to electrons that participates in a chemical reaction by accepting an electron pair in order to bond to a nucleophile. Because electrophiles accepts electrons, they are Lewis acids (see acid-base reaction theories). Most electrophiles are positively charged. In chemistry, a nucleophile (literally nucleus lover) is a reagent which is attracted to centres of positive charge. A nucleophile participates in a chemical reaction by donating electrons to a species known as an electrophile in order to form a chemical bond. Because nucleophiles donate electrons, they are by definition Lewis bases (see acid-base reaction theories). ... In Organic chemistry, a radical substitution reaction is a substitution reaction involving free radicals as a reactive intermediate.
2016-04-10 12:28:57
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answer #5
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answered by ? 4
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Hi. Here is a good answer. : http://www.answers.com/main/ntquery?s=Nucleophilic+Substitution&gwp=13
2007-02-10 01:31:07
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answer #6
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answered by Cirric 7
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