prove that if a|b then a^2 | b^2
a and b are integers
2007-02-10 00:48:53 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a|b
so, b=ka, where k is a natural number.
Squaring both sides, we find,
b^2 = k^2*a^2
i.e., b^2 = (some natural number) * a^2
i.e., a^2 | b^2
Hence Proved.
2007-02-10 00:58:08 · answer #1 · answered by Kristada 2 · 0⤊ 0⤋
It is equal because itis just lyk the ratio of the areas of a polygon and its sides... the area of the bigger polygon over the area of the smaller polygon is equal to the square of one side of the bigger polygon over the square of one side of the smaller polygon.
2007-02-10 01:02:38 · answer #2 · answered by Steph_kinse 2 · 0⤊ 0⤋
i don't know what that line means but you could just plug in numbers
a= 3
b=4
3 l 4
a2= 9
b2= 16
9 l 16
??????????
2007-02-10 00:57:37 · answer #3 · answered by limallama 4 · 0⤊ 0⤋