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2007-02-09 22:19:09 · 3 answers · asked by Lyla 3 in Science & Mathematics Chemistry

3 answers

ey your question is not clear. Any how see this may help you.
if you want find out concentration of unknown concentrated KMnO4 SOLUTION experimentally you should titrate that one with a standard solution of either oxalic acid or ferrous ammonium sulphate or hydrogen peroxide.
if you know the concentration in molarity and want to find out normality theoretically then we can do on the basis of the reaction in which it is participated.
for example if you find the molarity with the titration either with oxalic acid or ferrous ammonium sulphate then devide molarity with 5 because in these reactions KMnO4 changes to Mn+2 [MnSO4] where oxidation state change of Mn is 5. these reactions are taking place in acidic medium.
if you find the molarity with H2O2 then devide the molarity with 3
because oxidation state change of Mn is 4. MnO2 forms in this reaction.

2007-02-09 23:31:52 · answer #1 · answered by manidhar 2 · 1 1

normality =eqwalent weight/litre of solution=0.05N FOR KMno4
so molar mass of kmno4 =158g
if it is in acidic solution then valency =5
if in neutral sol. then =3
if in basic then =1
YOU DO SIMPLY ONE THING GO TO LAB TAKE 10 ML OF MOHR'S SALT OF M/50 CONC.,TAKE IT IN ACONICAL FLASK,ADD A LITTLE SULPHURIC ACID,TAKE KMNO4 IN A
BURRETTE.
ADD KMNO4 SLOWLY INTO THE FLASK TILL THE THE COLOR OF THE SOLUTION TURNS FROM COLORLESS TO PINK. FOR ABOUT 9.1-9.3mlOF KMn04 the titration is com-plete
then from the formula
THAT 5 MOLE OF MOHR'S SALT REQUIRES 1MOLE OF KMno4 for titration .we can write
5M'V'=MV
then you can also calculate the strength of KMno4,which is
=1.745g/l

2007-02-09 23:32:38 · answer #2 · answered by aman 1 · 1 1

Just go in chemistry lab and titrate it with oxalic acid of given normality

2007-02-09 22:22:58 · answer #3 · answered by cutiepie 3 · 0 2

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