The problem that I am having trouble on is
2/5-y/y-2.
The way that it is set up looks like this
2 y
-- - ------
5 y-2
if that makes any sense I am sorry I tried to set it up the best I could. Any help wil be greatly appreiciated. Thank you in advance!
2007-02-09 22:11:12 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I forgot to let you guys know that I am tring and this is what I have got can I just get some insight to whether I am doing it right or not
I have got
2/5-1-2
2/5-3
(2-15)/3
-13/3
so I have the answer as -13/3 but that just does not seem right
2007-02-09 22:19:01 · update #1
I am not sure if this will make it any more clear but it is worth a try
(2/5)-(y/y-2) so this is 2/5 minus y over y-2
2007-02-09 22:21:24 · update #2
multiply by (5) (y-2) = 2y - 4 - 5y = 0
-4 -3y = 0 ...add 3y to both sides
-4 = 3y divide by 3
y = -4/3 = - 1 1/3
2007-02-09 22:16:46 · answer #1 · answered by tom4bucs 7 · 0⤊ 0⤋
2/5 - y/y - 2 = x
2/5 - 1 - 2 = x
2/5 - 3 = x
-2 3/5 = x
2007-02-10 08:12:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2/5-y/y-2 y/y= 1
2/5-1-2
2/5-3 -3 = -15/5
-15/5+2/5= -13/5
-13/5 = -2 3/5
2007-02-10 06:45:14 · answer #3 · answered by Max 6 · 0⤊ 0⤋
This answer is based on what I understood from your question.
It seems like you want to solve: (2/5) - y/(y-2) = 0
Then,
Multiply your equation by 5 to get:
(2/5)*5 - y*5/(y-2) = 0*5
2 - 5y/(y-2) = 0
Now, multiply the last equation by (y-2) to get:
2*(y-2) - 5*y*(y-2)/(y-2) = 0*(y-2)
2*(y-2) - 5*y = 0
Now, expand the obtained equation:
2*y - 2*2 - 5*y = 0
-3*y - 4 = 0
Subtracting -4 from both sides of the equation:
-3*y - 4 - (-4) = - (-4)
-3*y - 4 + 4 = 4
-3*y = 4
Now, divide through by -3 to get your final answer:
y = - 4/3
Hope this is correct and useful.
2007-02-10 06:29:27 · answer #4 · answered by ma31ab 3 · 0⤊ 0⤋
2/5 - y/y-2 = 0
cross multiply
2y - 4-5y = 0
-3y = 4
y=4/-3 or -4/3
2007-02-10 07:01:05 · answer #5 · answered by Anonymous · 0⤊ 0⤋
The problem you have listed is unsolvable. It's not an equation. IT has to be equal to something inorder to solve it.
For ex>
(2y+2)/3= 1
What you listed is just an expression. If you tell me what it is equal to I can help.
2007-02-10 07:00:21 · answer #6 · answered by J B 2 · 0⤊ 0⤋
What kind of the problem is it ? Write the heading given above the problem in your book to make it understandable.
Just cancelling the y's would not be the soln.
2007-02-10 06:37:07 · answer #7 · answered by nayanmange 4 · 0⤊ 0⤋
your question is so disturbing.. i guess u better write it in words coz if not.. nobody can help u
2007-02-10 06:18:05 · answer #8 · answered by jara 3 · 0⤊ 0⤋