Organic Chem help - did I do this right?

Question

The other day I posted this question and I got put down for not being able to do it. I'm 13 and I'm trying to teach myself this stuff, so I've done a couple. Please just tell me if I'm on the right track or not!

The question is:
Write equations to show how the following changes could be brought about (write inorganic reagents on the arrow)

a) 1-chloropropane from propane
b)ethanal from ethane

What I've tried to do:
--------------------------


a) C3H8 ----(Cl2 UV light)--> C3H7Cl

b)C2H6----(OH- (aq))--->C2H4O

If you could even correct the formulas if I'm (I think I am) wrong, I'd really appreciate it, this chem book is old and doesn't explain it very well.

Thank you sooo much!!!

Answer 1

Lancenigo di Villorba (TV), Italy

You are 13-older?!?
You are a MYTH!!

QUESTION a)

CH3CH2CH3(g) + Cl2(g) ---> CH3CH2CH2Cl(g) + HCl(g)

by means of U.V. lamp acting on the gas mixture of propane and chlorine. 1-chloropropane is not the lonely product, besides it you obtain an EQUIMOLAR AMOUNT of 2-chloro-propane, as follows :

CH3CH2CH3(g) + Cl2(g) ---> CH3CH(Cl)CH3(g) + HCl(g)

Quenching operation (e.g. mixture chilling) permit you retrieve two products as liquid mixture while hydrogen chloride, propane and chlorine remain gas.
You wrote right, it is very difficult avoid 2-chloropropane.

QUESTION b)

As the former case, you start from a chlorination process in gas-phase, as follows :

H3C-CH3(g) + Cl2(g) ---> CH3-CH2Cl(l) + HCl(g)

The chilled liquid is "chloroethane" or "ethyl chloride".
The latter undergo a nucleophilic substitution in a second reactor, now in the liquid phase :

CH3-CH2Cl(l) + Na+OH-(aq) ---> CH3-CH2OH(aq) + Na+Cl-(aq)

so you retrieve a new stuff, as "ethanol" or "ethylic alcohol".
Now, you downstream the liquid mixture in a concentration tower where exceeding amount of water leaves the industrial apparatus at its "top of column". Once you have increased ethanol concenrtration, you execute a chemical oxidation, as follows :

5 CH3-CH2OH(aq) + 2KMnO4(aq) + 3 H2SO4(aq) --->
---> 5 CH3-CHO(aq) + 2 MnSO4(aq) + K2SO4(aq) + 8 H2O(aq)

This chemical way pollute ethanal with ethanoic acid,
e.g. CH3-COOH.

YOU HAVE ALSO ANOTHER FEATURE.
You start from a gas process, as follows :

H3C-CH3(g) ---> CH2=CH2(g) + H2(g)

where platinum's catalyst permit you dehydrogenation events ; you obtained "ethylene".
The latter undergo a chlorination process in a second reactor, again in the gas phase :

CH2=CH2(g) + Cl2(g) ---> ClCH2-CH2Cl(l)

so you retrieve a new stuff, as "1,2-dichloroethane" or "DCE", chilled as in its liquid form by quenching operations.
Now, you treat the latter in a third reactor where it undergoes a thermal decomposition, as follows :

ClCH2-CH2Cl(g) ---> CH2=CHCl(g) + HCl(g)

obtaining "vinyl chloride" or MVC. In a pressure's vessel, MVC flows inward a liquid mixture of sodium amide in anhydrous ammonia. You have this reaction :

CH2=CHCl(g) + NaNH2(liq.amm.) --->
---> HC#CH(g) + NaCl(liq.amm.) + NH3(liq.amm.)

where # means C-C TRIPLE BOND in acetylene molecule.
Finally, acetylene flows in an aqueous medium containing mercury sulphate and sulphuric acid. The reaction is :

HC#CH(g) + H2O(aq) ---> CH3CHO(aq)

You obtained ethanal.

Good luck for your future in Chemistry's amazing world!!

Answer 2

O - chem in all fairness confusing yet whilst u focus in college and learn on a daily basis, of course do all of the homework you will desire to be great. Biochem hobbies me individually this is why I took it and confident is that that's far less complicated than O - chem even though it is not basic as an entire. in simple terms practice and do all homework. the ideal suggestion i provides you is to comprehend the innovations of chem and bio genuine and study the textbook thoroughly

Answer 3

YA U ARE RIGHT... except in the first rxn, since propane is the secondary alkane , it has two substitution final products namely 1-chloropropane and 2-chloropropane(place -cl atom in the centre carbon atom)
the second rxn is correct. study well dear.

Answer 4

all u need is to add a bit of heat and cl2 to make chloropropane from propane.

ethanol....from ethane......C2H6+H2O-->C2H5OH+H2

Answer 5

a) this is the partially correct .. bcz UV light is a strong agent which can initiate the reaction very fast .. but there will be some byproducts will also be............
b) this is correct one