(2+h)^3
= (2+h)(2+h)(2+h)
First, calculate (2+h)(2+h)
= 2(2) + 2(h) + 2(h) + h^2
Combine like terms:
= 4 + 4h + h^2
Now you have:
(2+h)(4 + 4h + h^2)
Now you need to multiply each term again:
(2+h)(4 + 4h + h^2)
2(4) + 2(4h) + 2(h^2) + h(4) + h(4h) + h(h^2)
= 8 + 8h + 2h^2 + 4h + 4h^2 + h^3
Now combine like terms:
= 8 + 12h + 6h^2 + h^3
2007-02-09 21:35:54
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answer #1
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answered by Mathematica 7
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(2 + h)^3 {can also be written as...}
= (2 + h)*(2 + h)*(2 + h) {First do the calculation of (2 + h)*(2 + h)}
= (2 + h)*(2*2 + 2*h + h*2 + h*h) {Now, simplify the expansion}
= (2 + h)*(4 + 4h + h^2) {Now, multiply the obtained expression by (2 + h)}
= 2*4 + 2*4h + 2*h^2 + 4*h + 4h*h + h*h^2 {Simplify your obtained expression}
= 8 + 8h + 2h^2 + 4h + 4h^2 + h^3
= h^3 + 6h^2 + 12h +8 {This is the answer you want}
Hope this helps!
2007-02-10 06:19:28
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answer #2
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answered by ma31ab 3
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Solve (2+h)^3 (without plugging into a formula):
(2+h)^3 = (2+h)(2+h)(2+h)
(2+h)(2+h) = (4 + 2h + 2h + h^2)
Simplify (combine terms/rearrange from highest power to lowest)
(2+h)(2+h) = (h2 + 4h + 4)
(2+h)(2+h)(2+h) = (h^2 + 4h + 4)(2 + h)
= (2h^2 + h^3 + 8h + 4h^2 + 8 + 4h)
Simplify (combine terms/rearrange from highest power to lowest)
(2+h)^3 = (h^3 + 6h^2 + 12h + 8)_______****ANSWER****
2007-02-10 07:30:06
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answer #3
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answered by H. Scot 4
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theoretically there exits a formula
(a+b)^3 = a^3 +3ba^2+3a b^2+b^3
which gives here (2+h)^3 = 8 +12h + 6h^2 +h^3
we will check step by step
(2+h) ^3 = (2+h)^2*(2+h)
(2+h)^2* = 4+4h +h^2
and (4+4h +h^2) (2+h)= 8+8h+2h^2+4h+4h^2+h^3
2007-02-10 06:00:34
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answer #4
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answered by maussy 7
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(2+h)^3
=2^2+3.4.h+3.2.h^2+h^3.......
this is a formula a^3+3a^2b+3ab^2+B^3
=4+12h+6h^2+h^3...ur answer
or u can do it like (2+h)^2 X(2+h)
=(4+4h+h^2)(2+h)
=8+8h+2h^2+8h+4h^2+h^3
8+12h+6h^2+h^3..ur answer again.
2007-02-10 05:33:56
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answer #5
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answered by tonima 4
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(2+h)^3=?
coefficients comes from pascal triangle
1
3
3
1
remember
(a+b)^3=a^3+3a^2b+3a b^2+b^3
here a=2
b=h
then
(2+h)^3
=2^3+3*2^2*h+3*2*h^2+h^3
=8+12h+6h^2+h^3
2007-02-10 05:35:12
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answer #6
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answered by iyiogrenci 6
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(2+h)3=(2+h)(2+h)(2+h)
=(h2+4h+4)(2+h)
=h3+6h2+12h+8
2007-02-10 05:38:03
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answer #7
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answered by Cheng Zhi Lim 3
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it can be seperated in two.. (2+h)^2 (2+h)... square (2+h) , it will giv u h^2+4h+4. then multiplt it by (2+h)....
thats the answer... solve it..
2007-02-10 06:21:21
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answer #8
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answered by jara 3
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squared = ^2
x(quared) = x^2
cubed=^3
x(cubed) = x^3
2007-02-10 05:30:27
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answer #9
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answered by Rhul s 2
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