Strange Maths Problem?

Question

This is a maths problem that has some easy bits and hard bits. It goes like this:

By using only the plus, multiply, bracket, subtract and divide signs, place them in the gaps to get the numbers 1 - 24

A sample row looks like this

1 2 3 4 = 1

So an example is:

1 + 2 + 3 + 4 = 10

and you have to get all of the numbers from 1-24

Good luck!

Numbers must be in order as so

1 2 3 4

You cannot change order of numbers

Answer 1

This is as far as I could get, trying to leave the four numbers on the same position.

[(1*2)+3]-4 = 1
(1*2*3)-4 = 2
1+(2*3)-4 = 3
-1-2+3+4 = 4
[(1+2)*3]-4 = 5
1-2+3+4 = 6
[(-1+2)*3]+4 = 7
-1+2+3+4 = 8
-1-2+(3*4) = 9
-(1*2)+(3*4) = 10
1+[(2*3)+4] = 11
(-1+2)*(3*4) = 12
[(1+2)*3]+4 = 13
(1*2)+(3*4) = 14
1+2+(3*4) = 15
(-1+2+3)*4 = 16
3(2 + 4)–1 = 17
3(2 + 4)*1 = 18
-1+[(2+3)*4] = 19
1*[(2+3)*4] = 20
(1+2)*(3+4) = 21
2(3 4 – 1) = 22
-1+(2*3*4) = 23
1*2*3*4 = 24

Answer 2

Calculate the climate of each and every little thing in contact. The purple triangle has an area of 12 squares, the blue triangle has 5 squares, the orange shape has 7, and the eco-friendly shape has 8. The sum of those style of components is 12 + 5 + 7 + 8 = 32 squares. Now calculate the element of the super "triangle". If it fairly replace right into a triangle the section would be (5 × 13) / 2 = 32.5. word the ½ sq. discrepancy. The enclosing figures are no longer certainly a triangles in any respect: the blue triangle has a gradient of two / 5 = 0.4, and the purple triangle has a gradient of three / 8 = 0.375. The thick black lines help in deceiving the attention into seeing the 'hypotenuse' as a at cutting-edge line. instead what you have are a pair of quadrilaterals. interior the commencing up case, the form is concave (bends inward) to truly be an area of 32. interior the 2nd, it bends outward to be an area of 33 (much less the single sq.). So certainly no longer something is lacking... see the related drawing. determine 3 shows the differing gradients with exaggerated shapes. determine 4 shows how determine 2's "bulge" in its hypotenuse made area for the hollow.

Answer 3

(4-3)*(2-1)=1

2+4-3-1=2

(4-3)+(1*2)=3

(2*4)-(1+3)=4

2*4-(1*3)=5

(3*4)/(1*2)=6

(4-1)*3-2=7

(1+(3-2))*4=8

4+(1*3)+2=9

1+2+3+4=10

(3*4)+1-2=11

(2-1)*(3*4)=12