A 1.20 102 kg crate is being pushed across a horizontal floor by a force that makes an angle of 30.0° below the horizontal. The coefficient of kinetic friction is 0.400. What should be the magnitude of , so that the net work done by it and the kinetic frictional force is zero?
2007-02-09 18:06:39 · 3 answers · asked by mark m 1 in Science & Mathematics ➔ Physics
Yah, I think your q has problems. "1.20 102 " That's 1.20 times 102? I get 122.4.
Or wait - 1.20*10^2? Is that what you mean. To get the ^ symbol hold the shift and hit 6.
" the magnitude of ," of what?
Reading between the lines, the best I can do is agree with Blood. If the crate stops, no work and no kinetic frictional force.
2007-02-10 13:54:07 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
if the crate stops.
2007-02-10 02:41:54 · answer #2 · answered by Blood 3 · 0⤊ 0⤋
fix your question
2007-02-10 02:09:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋