I am to find (a) f (0) (b) f (-2) & (c) f (1)
Having a hard time with linear equations someone please help.
2007-02-09 17:55:41 · 5 answers · asked by Christ' Soldier 2 in Science & Mathematics ➔ Mathematics
just put the given values of x into the function and evaluate
I'll rewrite the function in a form that makes it easier to evaluate in your head, but I'll write out the tedium anyway
f(x)= (x-1)*x-2
a) f(0) = (0-1)*0-2 = -2
b) f(-2) = (-2-1)*(-2)-2 = (-3 * -2) -2 = 6-2 = 4
c) f(1) = (1-1)*1 -2 = -2
2007-02-09 18:06:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(a) f(0)=0^2 -0-2 =-2
(b) f(-2)=(-2)^2 -(-2)-2
f(-2)=(4)+2-2 ==>f(-2)=4
(c) f(1)=(1)^2-1-2
f(1)=1-1-2 ===> f(1)=-2
2007-02-09 18:04:01 · answer #2 · answered by daddyspanksalot 5 · 0⤊ 0⤋
f(0) = (0)2 - 0 - 2
= - 2
f(-2) = (-2)2 - (-2) -2
= 4 +2 - 2
= 4
f(1) = (1)2 - 1 - 2
= -2
2007-02-09 20:10:26 · answer #3 · answered by Nijansh V 1 · 0⤊ 0⤋
just subst in!
(a) f(0)=0^2-0-2=-2
(b) f(-2)=(-2)^2+2-2=4
(c) f(1)=1^2-1-2=-2
2007-02-09 18:02:06 · answer #4 · answered by pigley 4 · 0⤊ 0⤋
f(x)=x^2-x-2 just substitute the numbers for x
a
f(0)=0^2-0-2
f(0)=-2
b
f(-2)=(-2)^2-(-2)-2
f(-2)=4+2-2
f(-2)=4
c
f(1)=1^2-1-2
f(1)=1-1-2
f(1)=-2
2007-02-09 18:02:22 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋