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a boat has a mass of 6800kg, its engines generate a drive force of 4100N. due west, while the wind exerts a force of 800N.due east and the water exerts a resistive force of 1200N due east.
what is the magnitude and direction of the boats acceleration?

2007-02-09 16:51:35 · 3 answers · asked by tico 1 in Science & Mathematics Physics

3 answers

Find the net force.

4100 -800 -1200 = 2100 N.

Acceleration = Force/mass.

a = 2100/ 6800 = 0.309 m/s^2.

Since the acceleration is in the direction of net force, the direction is toward west.

2007-02-09 17:03:15 · answer #1 · answered by Pearlsawme 7 · 0 0

This is a significantly unrealistic story problem. The resistive force(friction) is related to the speed of the vehicle in relation to the fluid through which the vehicle is moving. These numbers might be instantaneously true but one could not predict much about the movement of the boat over any significant period of time.

That being said there is a net force of 2100 Newtons West and the vehicle has a mass of 6800 kilograms. divide the net force into the mass of the object being moved to obtain the instantaneous acceleration.

2007-02-09 17:02:03 · answer #2 · answered by anonimous 6 · 0 0

Fnet = ma

you know that Fnet is the sum of forces.

left: negative
right: positve

west (left): 41,000N
East (right): 1200N and 800N

1200N + 800N - 41,000N = (6800kg)a
-39,00N = (6800kg)a
a= -5.74m/s^2

the negative means to the left.

opps! i typed 41000N intead of 4100N. Probably you have to calculate again.

2007-02-09 17:02:11 · answer #3 · answered by      7 · 0 0

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