In the redox equation: 2MnO4,- + 5H2SO3-->2Mn,2+ + 3H2O + 5SO4,2- + 4H+ what is?

Question

In the redox equation: 2MnO4,- + 5H2SO3-->2Mn,2+ + 3H2O + 5SO4,2- + 4H+ what is the change in the oxidation number of the element that is oxidized? Enter your answer as a number with the correct sign, for example, -3 or +2.

Answer 1

The oxidation number of S is changed from -4 to in (H2SO3) to -6 in SO4,2-. The oxidation number of Mn is changed from +7 in MnO4, -1 to +2 in Mn.2+.
Therefore, S was oxidized the change= -6+-4=-2

Answer 2

S is oxidised from +4 to +6, an upward change of 2.
So I suppose they want you to write "S: +2" as the answer.