What charge (magnitude as well as direction) should be placed exactly on the mid point of the line segment joining two identical charges, each with a charge of Q coulombs? Please explain.
[The answer is: -Q/4 coulombs].
2007-02-09 16:00:08 · 4 answers · asked by Kristada 2 in Science & Mathematics ➔ Physics
The charge should be placed such that all the three charges are in equilibrium.
2007-02-10 00:23:28 · update #1
To achieve what effect?? You are missing something.
2007-02-09 19:12:30 · answer #1 · answered by hello 6 · 0⤊ 0⤋
as to keep the charge at d mid-pt. we have 2 maintain d force of attraction between d new charge and the each one of the old charge equal to the force of repulsion between the two old charges.
let us suppose the old charges=Q coulombs
and d new charge= -x coulomb
and the half length of the line segment=r mtr.
therefore, K Q*Q/(2r)^2=K Q*x/r^2
--->K Q^2/4r^2=K Qx?r^2
from above we get
x=Q/4
2007-02-10 08:07:16 · answer #2 · answered by $#Romeo Boy#$ 2 · 0⤊ 0⤋
A unit of matter in a particle is known as charge.
these charges contain a no. of electrified electrons
2007-02-10 07:16:14 · answer #3 · answered by keerthika 1 · 0⤊ 0⤋
force on the MIDPOINT WILL BE ZERO DUE TO ACTION &REACTION FORCES BEING EQUAL
2007-02-10 07:52:28 · answer #4 · answered by aman 1 · 0⤊ 0⤋