How far will a stationary golf ball roll if hit by a putter at X velocity?

Question

I used this to determine the velocity of the putter at the impact point:


PE + KE (top of putter backswing) = PE + KE (bottom of putter swing-when it is vertical and impacting the ball)


H=.055m (this is based on a 20 degree backswing from vertical position)

g=9.8m/s^2

m=.46kg


(H*G*M)+KE(top)= 0+1/2(M)(V^2)

(.055m)(9.8m/s^2)(.46kg) + 0 = 0 + 1/2(.45kg)(V^2)

(.243kg*m^2/S^2)=(.225kg)(V^2)

V=1.05m/s


Coefficient of friction:

.105 for this surface


Impulse time at putter impact with golf ball:

.005 seconds

Answer 1

The work done by the frictional force to stop the ball is the change in th KE which is the initial value.
It is also force x distance, that is the normal force N coefficient of friction x distance. so
1/2mv^2=Nud solve for d