If 6 is subtracted from the largest of three consecutive odd integers, with this result multiplied by 2, the answer is 23 less than the sum of the first and twice the second of the integers. Find the integers.
2007-02-09 15:35:46 · 5 answers · asked by whattheheck 4 in Education & Reference ➔ Homework Help
(x + 2 ) + (x + 2 + 1) + (x + 2 + 2 -6)= 2x
3x + 9 -6 = 2x
3x + 3 = 2x
-3x -3x
3= -1x
-3 = x (this makes no sense to me, I don't understand this...... help........)
2007-02-09 15:45:18 · update #1
15,17,19
2(x=4-6) = x + 2(x+2) - 23
2x + 8 -12 = x + 2x + 4 -23
8 - 12 + 19 = x
15 = x
x is the lowest integer, so you add two twice and get 15,17,19
2007-02-09 15:49:54 · answer #1 · answered by Chris P 2 · 1⤊ 0⤋
1st Method:
Assuming this is right: (x + 2) + (x + 2 + 1) + (x + 2 + 2 - 6)= 2x
3x + 3 = 2x (Subtract 2x on both sides to get x + 3 = 0... then subtract the 3)
x = - 3
2nd Method:
15,17,19
2(x=4-6) = x + 2(x+2) - 23
2x + 8 -12 = x + 2x + 4 -23
8 - 12 + 19 = x
15 = x
x is the lowest integer, so you add two twice and get 15,17,19
3rd Method:
x = first number
y = second number = x+2
z = third number = x+4 = y+2
now you build your equations
2*(z-6) = x + 2y - 23
2*(x+4-6) = x +2*(x+4) - 23
you operate
2x -4 = x +2x +8 -23
and you solve for x, the 2x's become 0
x = 23-8-4
x = 11
and you get the other numbers
x = 11
y = 13
z = 15
hope this helps
2007-02-09 23:57:30 · answer #2 · answered by Ghost 2 · 1⤊ 0⤋
Let x = an unknown integer
2x = an even integer
2x + 1 = an odd integer
2x + 3 = next higher odd integer
2x + 5 = highest of three consecutive odd integers
Equation: 2[(2x+5) - 6] - 23 = (2x+1)+2(2x+3)
Solution: 2(2x-1) - 23 = 6x + 7
4x - 25 = 6x + 7
-2x = 32
x = -16
So substituting -16 for x we have:
1st integer 2(-16) + 1 = 33
2nd integer: 2(-16) + 3 = 35
2rd integer: 2(-16) + 5 = 37
Let me know if this solution is correct.
2007-02-10 00:07:05 · answer #3 · answered by SoCal2007 2 · 0⤊ 0⤋
Assuming this is right: (x + 2) + (x + 2 + 1) + (x + 2 + 2 - 6)= 2x
3x + 3 = 2x (Subtract 2x on both sides to get x + 3 = 0... then subtract the 3)
x = - 3
2007-02-09 23:49:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Ok, here is how i did it
x = first number
y = second number = x+2
z = third number = x+4 = y+2
now you build your equations
2*(z-6) = x + 2y - 23
2*(x+4-6) = x +2*(x+2) - 23
you operate
2x -4 = x +2x +4 -23
and you solve for x, the 2x's become 0
x = 23-8
x = 15
and you get the other numbers
x = 15
y = 17
z = 19
hope this helps
2007-02-09 23:52:30 · answer #5 · answered by mensajeroscuro 4 · 1⤊ 0⤋