(4x^2y)/(z^3) divided by 2xyz
2007-02-09 15:33:11 · 4 answers · asked by music man 2 in Science & Mathematics ➔ Mathematics
2x/(z^4)
2007-02-09 15:39:33 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋
to divide by 2xyz you can multiply by its reciprocal 1/2xyz
then cancel 4x^2y with the 2xyz ; The 2 cancels with the 4 leaving a 2 the x cancels with the x^2 leaving an x and cancel the y's. Then when all of the cancelling is done just multiply straight across the numerator and straight across the denominator. You get (2x)(1)/(z^3)z= 2x/z^4
2007-02-09 15:41:57 · answer #2 · answered by lizzie 3 · 0⤊ 0⤋
(4 * x * x * y) / (z * z * z) / (2 * x * y * z)
Note : (a/b)/c = a / bc
therefore
(4 * x * x *y) / (z* z *z *2*x*y*z)
= 2 * x / z * z* z* z
= 2x / z^4
2007-02-09 15:42:41 · answer #3 · answered by @rrsu 4 · 0⤊ 0⤋
answer is :
2X / Z^4
2007-02-09 15:52:11 · answer #4 · answered by MAZ 3 · 0⤊ 0⤋