On a frictionless surface, a 0.35 kg puck moves horizontally to the right (at an angle of 0°) and a speed of 2.3 m/s. It collides with a 0.23 kg puck that is stationary. After the collision, the puck that was initially moving has a speed of 2.0 m/s and is moving at an angle of −32°. What is the velocity of the other puck after the collision?
2007-02-09 14:47:04 · 1 answers · asked by Chris 1 in Science & Mathematics ➔ Physics
Say the puck is traveling in the x direction. Then the initial total momentum of the system is .35 * 2.3 kg m/sec in the x direction, and 0 in the y direction.
This has to be sum of the total momentum of the pucks after the collision. So take what you are given for the one puck, break it down into x and y momentum, and calculate the x and y momentum of the other puck. Then divide by .23 kg to get the x and y velocity.
2007-02-09 14:53:22 · answer #1 · answered by Curt Monash 7 · 2⤊ 0⤋