It appears too much
2007-02-09 14:13:36 · 15 answers · asked by Anonymous in Computers & Internet ➔ Internet
If you don't want a virus, don't click it. Also, there are many sites that "give you a free laptop" by making you sign up for something, and by doing this you are also wasting your money. Turn on the popup-blocker by clicking "Tools," "Internet Options", and then "Privacy" in IE and you will see the Popup-Blocker Settings. Many toolbars also have the Popup-Blocker Option, like Google Toolbar. If the ad is not a pop-up, simply ignore it.
TheMafiaLeader
2007-02-09 14:20:18 · answer #1 · answered by the_mafia_lead3r 1 · 1⤊ 0⤋
get an ad-ware and spy-ware scanner (like ad-aware or spy bot search and destroy) and scan that should get rid of them. Usualy you have to sign up for like 5 other things at like $9 a month to get your "free laptop".
2016-05-24 19:35:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I think scam. It comes up on everyones computer if you don't use pop up blockers and if everyone got one, the companies would be out of business.
2007-02-09 14:16:51 · answer #3 · answered by justa 7 · 2⤊ 0⤋
It's just a scam to lure you into believing it.. Get a pop up blocker.
2007-02-09 14:17:43 · answer #4 · answered by Nonsensical 2 · 2⤊ 0⤋
I think they are a pain in the but. It's a scam and I guess there is nothing we can do about it.
2007-02-09 14:24:35 · answer #5 · answered by Anna Hennings 5 · 1⤊ 0⤋
I think to myself 'I wonder if anyone is stupid enough to think they REALLY won a laptop'
2007-02-09 14:21:54 · answer #6 · answered by Johnny Conservative 5 · 1⤊ 0⤋
I dont think, I close it out because I KNOW its a scam!
2007-02-09 14:16:32 · answer #7 · answered by Anonymous · 2⤊ 0⤋
I think... does anyone on the planet actually ever fall for those?
2007-02-09 14:17:13 · answer #8 · answered by justr 3 · 1⤊ 0⤋
Marangelyngrn ... Yes, they're all just scams.
2007-02-09 14:20:59 · answer #9 · answered by Anonymous · 1⤊ 0⤋
I wonder when the adds get better!
2007-02-09 14:24:03 · answer #10 · answered by GioDiAqua 1 · 1⤊ 0⤋