The apparent visual magnitude of a star is 7.3. This tekks us that the star is.
a) One of the brightest stars in the sky
b) bright enough that it would be visible even during the day
c) not visual with the unaided eye
d) very far from the Earth
e) Very close to Earth
2007-02-09 11:44:59 · 3 answers · asked by Helen 1 in Science & Mathematics ➔ Astronomy & Space
Hi. Magnitude of 0 is pretty bright. Negative magnitude is even brighter. A mag 7.2 star is pretty dim. So...
2007-02-09 11:58:35 · answer #1 · answered by Cirric 7 · 0⤊ 0⤋
C
Further:
The idea of "apparent magnitude" goes all the way back to the Greek astronomer Hipparchus. Basically, he looked at the stars in the sky and classified them by how bright they appear -- the brightest stars were "magnitude 1", the next brightest were "magnitude 2", etc., down to "magnitude 6", which were the faintest stars he could see. It is this basic classification from over 2,000 years ago that led to the magnitude scale we have now!
This was copied from the site: http://curious.astro.cornell.edu/question.php?number=569
2007-02-09 20:19:59 · answer #2 · answered by V. 3 · 0⤊ 0⤋
The answer is C. Given a clear sky, the unaided eye can see stars as dim as 6.0 in magnitude. 7.3 is far too dim. The lower magnitude a star is, the brighter it is. Sirius is the brightest star in the sky at -1.47.
2007-02-09 21:07:33 · answer #3 · answered by Tikimaskedman 7 · 0⤊ 0⤋