A 0.4505 g sample of CaCO3 was dissolved in a small amount of concentrated HCl and the resulting solution diluted to 250.0 ml. A 25.00ml sample of the solution required 24.25 ml of an EDTA(2-) solution for titration.
1) How many moles of CaCO3 were used?
2) What is the concentration of Ca2+ in the 250.0ml of CaCl2 solution?
3) How many moles of Ca2+ are contained in a 25.00 ml sample?
4) How many moles of EDTA are contained in the 24.25 ml used for titration?
5) What is the concentration of the EDTA solution?
HELP ME PLEASE FOR THIS QUESTION....U DONT REALLY NEED TO SHOW ALL WORK...PLEASE SIMPLY JOT WHAT U GET FOR AN ANSWER WITH LITTLE EXPLANATION...THANK YOU!!!!
2007-02-09 04:44:14 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
You have 0.4505g of CaCO3. Now divide this by the Mr, 100, to get the moles. The concentration is 1000/250, or 4 times this. But you only took a 25/1000th of that solution into the pipette. The moles of EDTA in 24.25ml are the same as the number of moles of Ca2+ in the pipette. Now multiply that number of moles by 1000/24.25 to get the concentration of EDTA.
2007-02-09 05:50:33 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋