A 42 gram block of an unknown metal at 94.0oC was dropped into an insulated flask containing approximately 30.

Question

A 42 gram block of an unknown metal at 94.0oC was dropped into an insulated flask containing approximately 30.0 grams of ice and 25.0 grams of water at 0oC. After the system had reached a steady temperature it was determined that 9.0 grams of ice had melted. What is the specific heat of the metal? The heat of fusion of ice is equal to 333 J/g.

Answer 1

9 g of ice at 0 C turned into 9 g of liquid water at 0 C.

(333 J/g for ice) x 9 g of ice = 2,997 J of energy

The block went from 94.0 C to 0.0 C, a change in temperature of 94.0 C.

So the specific heat for the unknown metal is (2,997 J) / [(94.0 C) x (42 g)]

Units for the answer are J/ g C. and answer should be to 2 sig figs because the weight of your unknown was only reported to 2 sig figs.

BTW you might have more replies to your questions if you select a best answer, now and then. It would help your score too, and then you could ask more questions.