The specific heat of aluminum metal is 0.902J/gK. How much heat, in joules, is required to heat a 58.5 gram sample of aluminum from -6oC to 27oC? Enter your answer in scientific notation with no units.
2007-02-09 04:42:44 · 5 answers · asked by adam s 1 in Science & Mathematics ➔ Chemistry
The equation to do this problem is q(heat)=C(specific heat)*T(change in temperature)*m(mass)
Plug in and you get q=(0.902 J/gK)(27oC-(-6oC))(58.5g)
The units cancel out and you get 1741.31 J or 1.74 x 10^3.
2007-02-09 04:49:08 · answer #1 · answered by Josh 2 · 0⤊ 0⤋
Mass of the aluminium sample is 58.5 g and the temperature difference is 27 - (-6) = 33 C. Therefore, the answer will be
0.902 X 58.5 X 33
2007-02-09 04:48:34 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
Wow! I'll be getting my dog soon and the block off portion of the house she'll be staying in does have a vent. Right now we're dog proofing the space so I'll make sure that blocking off the vents or removing her collar is on the list! Thank you so much. All those little ifs and buts seem impossible until they happen!
2016-05-24 01:37:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1.74 x 10^3 J
2007-02-09 04:46:30 · answer #4 · answered by Vincent Y 2 · 0⤊ 0⤋
1108.107
2007-02-09 04:48:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋