at a constant velocity, what is the friction force that acts on the monkey?
is it the monkey holding onto the pole, or gravity pushing it down?
2007-02-09 01:40:13 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
F=ma, where F is force, m is mass, and a is acceleration.
If the monkey is moving with a constant velocity, then there is no net acceleration and therefore the net force on the monkey is zero.
The 2 forces acting on the monkey are gravity (pulling the monkey down) and friction (resisting the downward motion). They act in opposite directions with equivalent magnitude.
The friction force is equal to the monkey's weight:
F=(400kg)(9.81m/s^2)=3924N, acting in the upward direction.
The frictional force is due to the monkey holding onto the pole. Friction force is equal to the coefficient of friction multiplied by the normal force. The normal force is the force acting perpendicular to the interfacing surfaces.
2007-02-09 03:00:37 · answer #1 · answered by czimme3 4 · 0⤊ 0⤋
Gravity is not a friction force. Friction forces occur when 2 materials are in contact with each other. Here the monkeyis in contact with the pole so that is the friction force
2007-02-09 10:55:40 · answer #2 · answered by Glenn T 3 · 0⤊ 0⤋
In thinking about this question (it's been a while since I've done physics), both are a factor. However, the friction force is opposite to gravity.
2007-02-09 10:00:45 · answer #3 · answered by Grover 3 · 1⤊ 0⤋