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Consider both objects as water, in hard plastic containers. will they reach at the same time or almost at the same time or at diffrent times. need a scientific answer . which formula will be used to calculate?

2007-02-09 00:23:58 · 13 answers · asked by a novice on computers 1 in Science & Mathematics Physics

13 answers

Both of them would reach the ground at the same time.
According to galileo if a bodies of two different weights are dropped down at the same time, both the bodies will reach the ground at a time.
formula used to calculate is s=ut+1/2at^2
where 's' is the distance
'u' is the initial velocity i.e. 0
't' is the time taken
'a' is the accelaration due to gravity i.e. 9.8m/s^2

2007-02-09 00:47:23 · answer #1 · answered by Ray 2 · 1 0

This is not as straightforward as it sounds, as answered previously the two masses should fall at the same rate as their acceleration is goverened by gravity, so they accelerate at the same rate.

However, if both are containers of water, i.e. with the same density, the larger mass will have a larger volume, hence larger surface area. The larger surface area will contribute to more drag on the object as it falls through air hence a lower accleration due to:

F=ma

Where F is made up of mg (massXgravity) and an opposite force of air resistance or drag slowing the acceleration of the object.

Therefore in air the smaller mass will fall slower. In a vacuum they will fall at the same rate as the only force on the object if gravitational attraction so you get:

F=ma
F=mg
a=g

2007-02-09 00:52:15 · answer #2 · answered by Steve B 1 · 0 0

Both will strike ground at EXACTLY the same time, in vacuum. But since air gives air resistence, the one with the larger surface area will reach later, the time difference varying according to the ratio of the the surface areas of the two bodies. This fact was practically proved by Galileo, when he threw an iron ball & a very light object (do'nt remember what it was) & they both hit ground at almost the same time.

2007-02-09 02:08:07 · answer #3 · answered by Kristada 2 · 1 0

If there is no air resistance, both of them will take the same time to fall. U know that

velocity=displacement / time

acceleration= final -initial velocity / time.

u see that in neither in acc nor in velocity there comes a factor of mass.

There fore if u threw a feather and a iron block from the same height they ought to fall together but since there is air resistance on the earth the iron block will fall first. i dont know the value of air drag u ought to search for it u will get it.

2007-02-09 14:11:33 · answer #4 · answered by The Pain 2 · 0 0

Both the bodies reach simultaneously.It is already proved by GAGILEO who dropped two bodies of different masses from leaning tower of Pisa in 1549.The formula used is pertaining to the freely falling body,
time taken to reach the ground ---------t
acceleration due to gravity ---------------g
height from which they are dropped ----h
then,

t= (2h/g)^1/2

here a^b means "a to the power b"

2007-02-09 00:33:29 · answer #5 · answered by satwik 2 · 0 0

if you would have asked this 2 yrs ago...i could have answer you with a formula..for now, i know that gravity pulls on both items (2kg & 40 kg) with the same force (9.871 m/s square) therefore falling at the same time....a formula might be (hopefully im not wrong) d= v * t (?)

2007-02-09 00:33:40 · answer #6 · answered by Anonymous · 0 0

Both must reach at the same time if there is no other force fired on them

2007-02-09 01:41:39 · answer #7 · answered by R M 1 · 0 0

the speed at which an object falls is proportional only to acceleration (gravity) and time of flight and inversely proportional to drag or resistance to flight. Mass or weight do not figure into the time of flight.

Time of flight = 32 feet/second (squared) x time

2007-02-09 00:31:04 · answer #8 · answered by Sam E 6 · 0 0

Gravity affects objects the same no matter what their weight is. Theoretically they should hit the ground at the same time.

2007-02-09 00:30:50 · answer #9 · answered by Angry-T 5 · 0 0

both will reach the ground at the same time as time taken to fall is independent of mass(neglecting air resistance)

2007-02-09 00:31:38 · answer #10 · answered by arup s 6 · 0 0

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