log5(1/5)=?
log5= -(1/5)
since log5 = -(1/5) the value is = -1 the principles of Logarithm is that anything to the base of log is equal to 1 and since log5 is equivalent to (1/5) it's just simply -1
thus log 5(1/5) is = -1
2007-02-08 20:51:42
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answer #1
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answered by kittana 6
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By laws of logarithms, log(a/b) = log a - log b
Thus log(1/5) = log5(1) - log5 (5) = 0 - 1 = - 1
2007-02-09 04:59:56
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answer #2
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answered by Como 7
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Let log (1/5) base 5 = x
so 5^x = 1/5
5^x = (5)^-1
thus
x = -1 ( Comparing the powers)
2007-02-09 04:28:25
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answer #3
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answered by @rrsu 4
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-1
2007-02-09 05:52:35
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answer #4
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answered by Anonymous 2
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-1. Equivalently, 5^(-1) = 1/5.
2007-02-09 03:54:15
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answer #5
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answered by Anonymous
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logn(a/b)=logn(a) - logn(b) and logn(a*b)=logn(a) + logn(b).
2007-02-09 03:58:50
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answer #6
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answered by agent-X 6
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