6(x-2)+2(x-1)=3x-4
[6x-12] + [2x-2] = 3x-4
Now add the "x" terms and integers in the left hand side
8x - 14 = 3x-4
Bring the "x" terms on left hand side and integers on righ hand side
8x - 3x = -4 + 14
5x = 10
x = 10/5
x = 2
GREAT QUESTION
IT NEEDS A LOT OF PRACTICE
KEEP GOING
2007-02-08 19:42:47
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answer #1
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answered by natarajan@ezee 2
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6(x -2) + 2(x-1) = 3x - 4
6x - 12 +2x - 2 = 3x -4
8 x - 3x = -4 +14
5x = 10
x = 2
2007-02-08 22:20:54
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answer #2
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answered by Anonymous
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6(x-2)+2(x-1)=3x-4
6x-12+2x-2= 3x-4
8x-14=3x-4
8x-3x= -4+14
5x= 10
X= 2
2007-02-08 19:04:45
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answer #3
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answered by yogachaitanya 2
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hey that's an easy one
well it goes like this
6 ( x - 2 ) + 2 ( x - 1 ) = 3 x - 4
6x - 12 + 2x - 2 = 3x - 4
6x + 2x - 3x = - 4 + 2 +12
5x = 10
x = 2
2007-02-08 22:59:29
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answer #4
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answered by nirupa 2
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the CORRECT solution is:
6x-12+2x-2=3x-4
8x-3x=-4+14
5x=10
x=2
2007-02-08 19:09:57
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answer #5
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answered by Noraaa 1
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6x-12+2x-2=3x-4
8x-14=3x-4
8x-3x=14-4
bringin x to LHS and numbers to RHS
5x=10
x=10/5
x=2
2007-02-09 00:20:50
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answer #6
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answered by Anonymous
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6(x-2)+2(x-1)=3x-4
6x - 12 + 2x - 2 = 3x - 4
6x - 3x + 2x = 12 + 2 - 4
5x = 10
x = 2
2007-02-08 19:17:47
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answer #7
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answered by oohayim 2
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6(x -2) + 2(x-1) = 3x-4
6x-12+2x-2=3x-4
8x-14=3x-4
5x=10
x=2
:-)
2007-02-08 23:00:04
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answer #8
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answered by kural_akhi 1
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6(x-2)+2(x-1)=3x-4
6x-12+2x-2= 3x-4
8x-14=3x-4
8x-3x= -4+14
5x= 10
X= 2
2007-02-08 19:13:17
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answer #9
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answered by dailym 1
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6x-12+2x-2=3x-4
2007-02-08 19:21:59
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answer #10
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answered by balbir s 1
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