A merchant blends tea that sells for $3.05 a pound with tea that sells for $2.80 a pound to produce 90 lb of a mixture that sells for $2.95 a pound. How many pounds of each type of tea does the merchant use in the blend?
2007-02-08 18:25:09 · 4 answers · asked by Asking For It 3 in Science & Mathematics ➔ Mathematics
Can you also show me how you got the answer as well? Thanks
2007-02-08 18:32:42 · update #1
x*3.05 + (90 - x)* 2.80 = 90 * 2.95
mult by 100 both sides
305x + 90*280 - 280x = 90*295
25x = 90(295 - 280) = 90 * 15 = 1350
x = 1350/25 = 54
90-x = 36
=>
54 pounds of $3.05 tea + 36 pounds of $2.80 tea
(did the arithmetic in my head so check the figures)
2007-02-08 18:33:23 · answer #1 · answered by atheistforthebirthofjesus 6 · 0⤊ 0⤋
45
2007-02-09 02:30:04 · answer #2 · answered by Wattsup! 3 · 0⤊ 0⤋
2.80x + 3.05y = 2.95(x + y)
x + y = 90
x = 90 - y
2.80(90 - y) + 3.05y = 2.95*90
3.05y - 2.80y = 90(2.95 - 2.80)
0.25y = 90*0.15
y = 54 lb.
x = 36 lb.
2.80*36 + 3.05*54 =? 2.95*90
100.80 + 164.70 = 265.50
2007-02-09 03:10:27 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
.
2007-02-09 02:54:51 · answer #4 · answered by Jay 1 · 0⤊ 0⤋