2007-02-08 18:02:55 · 4 answers · asked by Melissa D 1 in Science & Mathematics ➔ Other - Science
Acceleration due to gravity is 9.81 m*s^-2.
Since D=1/2at^2, t=sqr(2D/a).
t=2.17 s
2007-02-08 18:08:47 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If we neglect air resistance and use the position function
s(t)=.5g^2+ vt + s, where v is the initial velocity, s is the initial height (23m), g=9.8m/s^2, and of course, t is time. This gives us the equation s(t)=4.9t^2 + vt + 23. Under normal circumstances, you would solve this problem by setting the function s(t)=0, then factor the equation and solve for t and "throw out" any extraneous solutions (i.e. those that are negative). However, depending on how hard and how high you jumped, you would need to specify an intial velocity in order to solve the problem. D=.5at^2 is used to find the distance starting from rest, and in this case would not be applicable because I'm assuming that you wouldn't just "fall off" what ever it is you jumped from into the river which could end in your untimely demise.
2007-02-09 20:07:37 · answer #2 · answered by k 1 · 0⤊ 0⤋
Yeah, I guess..
Let's call time as 't'
You've got the distance d = 23m
Acceleration due to gravity = 9.8m/s^2
Acceleration = Speed/ time.
Speed = acceleration* time. = 9.8*t
Time = distance/speed
t = 23/ 9.8t
Multiplying by t throughout, you'll get
t^2 = 23/9.8
t^2 = 2.346938.
Taking square roots throughout, you'll get:
t= 1.531972 seconds.
Hope I'm right!
Good luck!
2007-02-09 05:06:15 · answer #3 · answered by Smarty 2 · 0⤊ 0⤋
Count on the way down. One marshmellow, two marshmellow, thr...SPLASH!
2007-02-09 02:13:10 · answer #4 · answered by somathus 7 · 0⤊ 0⤋