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use trig definition to prove that sine of one angle= cosine of the other angle or that this is a false statement.

2007-02-08 16:06:36 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

sinA = opposite side to A / hypotenuse
= adjacent side to B / hypotenuse
= cosB.

QED.

2007-02-08 16:11:14 · answer #1 · answered by Anonymous · 0 0

Call one angle a and the other angle b. By definition a+b=90.

Furthermore, sin(90-x)=cos(x) [fundamental identity]
a=90-b
sin(a) = sin(90-b)
sin(a) = cos(b) .

2007-02-09 00:15:19 · answer #2 · answered by Milton's Fan 3 · 0 0

The three sides of a triangle can be labeled A, B and C opposite from angles a, b and c respectively.
If we let c be the 90 degree angle then
Sin(a)=A/C
Cos(a)=B/C
Sin(b)=B/C
Cos(b)=A/C

since both Sin(a) and Cos(b) are equal to A/C they are equal to each other.

since both Cos(a) and Sin(b) are equal to B/C they are equal to each other

2007-02-09 00:21:50 · answer #3 · answered by anonimous 6 · 0 0

yes they a complementary because they are both 45 degree angles making them together 90 degrees

2007-02-09 00:23:03 · answer #4 · answered by Anonymous · 0 1

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