What's the max. height and the speed if A ball is thrown from a point 1 m above the ground.?

Question

The initial velocity is 19.5 m/s at an angle of 28.1o above the horizontal.

Answer 1

Use V x V = U x U + 2 A S
At maximum height, V = 0. U = 19.5 sin (28.1 deg), A = -9.8.
S is the only unknown.

The horizontal portion of the "speed" remains unchanged at 19.5 cos (28.1 deg). The vertical portion is maximum just before hitting the ground. Use above formula to work out Vmax x Vmax = U x U + 2 A S using U= - 19.5 sin (28.1) (minus because of opposite direction), A = 9.8, S = 1.

Answer 2

H= (u.u.sinA.sinA)/(2g)