English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I've been trying to go through pages of results from google and questions asked here, and they're either too complicated or not quite what I have

On the sheet it tells me to find the slope and y intercept of the line. People that need help put out problems that go "y=2x - 3" which doesn't match up with mine.
the first one starts off with:

4y - 2x = -10

now I "think" that the formula is y =mx+b (teacher didn't gave it once in the middle of a problem), m being the slope and y being the intercept so does that mean that..

y is 10 and m=2?

I've struggled with math almost all my life and I'm really stuck on this, any help would be appreciated.

2007-02-08 15:32:00 · 6 answers · asked by Redrum 1 in Science & Mathematics Mathematics

-5y+3x=4

do i..

subtract 3x to both sides 5y+3x-3x=4-3x
then divide by 5y after the work with 3x so it will look like y=(4/5)-(3x/5)

then

y= (-3/5)-(4/5)

m= -3/5
slope= 4/5

did i do this correctly or am i still wrong?

2007-02-08 16:26:14 · update #1

6 answers

The slope intercept method works when the equation has been transformed into a problem that has the same answers but has the form y=mx+B
4y-2x=-10 is not in the right form.
the first step is to get the y term and the x term on opposite sides of the equal sign.
to do this add 2x to both side of the equation.
4y-2x+2x=2x-10
4y=2x-10
then we notice that the y term has a coeficient other than the number one. To rectify that situation divide both sides by 4
4y/4=2x/4-10/4
y=1/2x-5/2
The equation is now in the form y=mx+b
m=1/2
b=-5/2
The slope is 1/2
The y intercept is -5/2

2007-02-08 15:47:37 · answer #1 · answered by anonimous 6 · 0 0

You take your equation: 4y - 2x = -10 and make it take on the shape
y = mx + b

Thus:

4y = 2x - 10 (from adding 2x to each side) then

y = (1/2)x - 5/2 (from dividing each side by 4 and reducing on the right)

so your slope m = (1/2);

your y-intercept, the point where your line intersects the y-axis, is -5/2, the "b" in your model equation.

2007-02-08 23:44:39 · answer #2 · answered by answerING 6 · 0 0

You have to take the problem given and find a way to fit it into the y = mx + b equation. To do this, you need to solve your equation for y.

4y-2x=-10
y-2/4x=-2 1/2
y = -2 1/2 + 1/2x

OR

y = 1/2 x - 2 1/2

Back to y = mx + b, where m is the slope and b is the y-intercept...

m (slope) = 1/2
b (y-intercept) = -2 1/2

Know what to do with it now?

2007-02-08 23:38:06 · answer #3 · answered by wise_ole_sage 2 · 0 0

All you have to do is re-arrange your equation so that it matches the form y=mx+b.

You formula is 4y-2x=-10.
You need to get y on one side by itself.

4y=2x-10
y=(1/2)x-(5/2)

Now the equation is in the form y=mx+b, where (1/2)=m and (-5/2)=b. m is the slope and b is the y-intercept.

2007-02-08 23:37:11 · answer #4 · answered by Milton's Fan 3 · 0 0

yes, your right, it's y=mx+b. if the statement given is 4y-2x=-10, then you can put parenthesis around the answers to help you.
(4y)+(-2x)=(-10). then you move everything that does not have a y variable to the other side, in this case, -2x, so you would get:
4y= 2x -10. it is a positive 2x because we switched it from one side to the other. then you make y=1, so you would divide by the coeficcient(sp=?), in this case, 4. so you would get y=1/2x-2and1/5. so m=1/2 and y=-2and one-fifth. hope that helps!

2007-02-08 23:42:57 · answer #5 · answered by Chris5519 2 · 0 0

Y=(-10+2x)/(4) or y=2x-10, here is your slope the coeficient of x, and your y intercept is -10.

2007-02-08 23:38:36 · answer #6 · answered by Anonymous · 0 0

fedest.com, questions and answers