physics question about elevators?

Question

If an elevator is moving upward at a constant speed, how would I find the apparent weight of a 95.0kg person standing on a scale?

Answer 1

w apparent = mg + ma

so if the elevator were accelerating upward w app. would be bigger than normal but since it is constant speed a=0 and
w = mg - that's in fact real weight.
therefore, moving with constant v is the same as being at rest.

NOTE: weight is not 95kg - that's MASS

weight = 95 * 9.8 newtons

Answer 2

Fill the elevator with water (and nothing else) Calculate the weight of the water on a test run. Throw the person in the water. Capture the water that escapes. Based on the amount of water displaced you can then determine the estimated weight of the person. Throw the scale in the water and again capture the displaced water and determine the weight of the scale.

the weight of the person + the weight of the scale - the initial weight of the water = the apparent weight of a 95.0kg person standing on a scale.

Conduct the experiment while moving the elevator at a constant speed.

Answer 3

If its moving at a constant speed, then the weight of things and people in the elevator is the same as if they were standing on the earth. It's only when the elevator accelerates that the weight changes.

Weight = mass x gravity
weight (in Newtons) = 95 kg x 9.8 m/s^2

Answer 4

The key word here is constant, in other words, no acceleration. Therefore, the apparent weight is the same as how much they weigh normally.

Think about riding an elevator. You only feel heavy or light during the stopping and starting portions of the ride.

Answer 5

At a constant speed the weight would show the same as if the elevator was at rest.

Answer 6

a) consistent velocity implies no stress. subsequently, it would examine sixty 8 kg. b) comparable. sixty 8 kg c) ok, so now think of being in an elevator that hurries up upward. you will experience heavier, superb? An accelerating elevator is similar to an inertial physique with downward stress of F = ma = (sixty 8 kg)(0.33g). This stress is the better "weight" that the size reads, so (sixty 8 kg)(0.33g) = Mg, so M = (sixty 8 kg * 0.33) = 22.4 kg. it rather is the better "mass", so the size reads a entire of: 22.4 kg + sixty 8 kg = ninety.4 kg d) comparable, in the different path: sixty 8 kg - 22.4 kg = 40 5.6 kg

Answer 7

You would say that he is only affected by the gravity. The elevator only applies a force if it is accelerating. Thus, he will weight 95 kg