absolute value of 2x - 5 <9
2007-02-08 14:36:38 · 9 answers · asked by ~*PrInCeSs*~ 2 in Science & Mathematics ➔ Mathematics
It Is not called absolute value it's an inequality. x<7
2007-02-08 14:45:41 · answer #1 · answered by BlackRose 2 · 0⤊ 0⤋
That means 2x-5 has to be less than 9 and also greater than -9.
So solve 2x - 5 < 9 AND 2x - 5 > -9, by the methods we've shown you in previous answers.
You should end up with x between -2 and 7, i.e.
-2 < x < 7
Notice emy is the only other answerer who's correct (up till now)
2007-02-08 22:43:17 · answer #2 · answered by Hy 7 · 0⤊ 0⤋
-2 < x < 7 or the open interval: (-2, 7)
emy and hy seem to have it right.
There would be less confusion perhaps if the quetion were framed:
{absolute value of [2x - 5]} < 9; solve for x
2007-02-08 22:43:46 · answer #3 · answered by answerING 6 · 0⤊ 0⤋
-9<2x-5<9 add 5 to three sides
-4 < 2x < 14 divide by 2
-2< x < 7 s.s. = ]-2,7[
2007-02-08 22:41:33 · answer #4 · answered by emy 3 · 0⤊ 0⤋
|x| < 7
Its the actual answer !!
The above onez dont make sense !!
when |x| > 7 .. then x can be 6 or -6 .. 5 or -5 .. 4 or -4 .. and so on !!
lets take 8 and -8
2|-6| - 5 < 9
12-5
7 < 9 TRUE !!
2007-02-08 22:41:42 · answer #5 · answered by MurtaZa 3 · 0⤊ 0⤋
2x<14 (add 5 to both sides
x<7 (divide 2 on both sides)
2007-02-08 22:39:39 · answer #6 · answered by Milton's Fan 3 · 0⤊ 0⤋
x= +or- 7
2007-02-08 22:39:38 · answer #7 · answered by schs_spartan 3 · 0⤊ 1⤋
x<7
2x-5<9
+5 to -5 ::: +5 to 9
2x<14
2x/2<14/2
x<7
did that work/help?
2007-02-08 22:43:42 · answer #8 · answered by ♥•Softball•Chick•♥ 4 · 0⤊ 0⤋
|4| prolly wrong cuz i just guessed a random number :)
2007-02-08 22:43:55 · answer #9 · answered by wazzup 1 · 0⤊ 0⤋