Why is it that 1/[(x-1)^2(x+3)] when using partial fractions gets divided up into:
A/(x-1), B/[(x-1)^2], C/(x+3) ??
My initial thought was to make it A/(x-1), B/(x-1), C/(x+3)...But that is wrong. Someone please tell me why.
2007-02-08 13:07:09 · 2 answers · asked by ben_ev0lent 1 in Science & Mathematics ➔ Mathematics
Your initial thought is wrong because you need a factor which takes care of the possibility of B/(x-1)^2. Having A/(x-1) and B/(x-1) doesn't make sense because the two can be combined into D/(x-1) by setting D = A + B. Your calculus book should have an example where the denominator is a product of linear factors, some of which are repeated.
2007-02-08 13:14:36 · answer #1 · answered by Milton's Fan 3 · 0⤊ 0⤋
what. i think your answer is right
A/(x-1)+B/(x-1)+C/(x+3) i got no idea y you got wrong
2007-02-08 13:12:28 · answer #2 · answered by phong pham 2 · 0⤊ 1⤋