A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 40 seconds. What is the length of the train in meters?
The answer is 400 METERS. can someone kindly explain how to arrive at that answer?
2007-02-08 11:40:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The easiest way to get this is to calculate the velocity of the train relative to the motorbike (you would measure this velocity if you would be sitting on the motorbike). This velocity is 100 km/h ─ 64 km/h = 36 km/h = 10 m/s. Now the length of the train is the distance of the train in respect to the motorbike: d = 10 m/s x 40 s = 400 m.
2007-02-08 11:51:00 · answer #1 · answered by Dorian36 4 · 0⤊ 0⤋
The question is "how far can a train travel in 40 sec. at 36kmph?" 100-64=36. 36000/3600=10. (converted to meters) we needed to find out how far it goes in 1 sec. Multiply by 40. Thats your answer. 400m.
2007-02-08 11:50:18 · answer #2 · answered by paulgarrison20002000 2 · 0⤊ 0⤋
To get the relative velocity, subtract 64 from 100.
distance = velocity times time
remember to convert
1km is 1000m and an hour is (60)(60)s=3600s
2007-02-08 11:45:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
to clean up #9 you may bear in concepts that velocity =Distance/Time so T=D/V in the experience that your chum walks 8km at 8.1km/h, the time would be T= (8km) / (8.1km/h) = a pair of million hour a while would be T= (8km) / (6.4km/h) = a pair of million.25hrs = 1hr 15 min the version is approximately quarter-hour
2016-11-02 22:39:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋