P=2L+2W
Where P is the perimeter of a rectangle with length L and width W. Find P if
L=16 km, W=7.5KM.
2007-02-08 07:54:26 · 12 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Not necessarily very smart, although modestly talented.
P=(2x16km) + (2x7.5km)
P=32km + 15km
P=47km
Hope this helps!
:-)
2007-02-08 08:11:43 · answer #1 · answered by bazz2202 3 · 1⤊ 0⤋
P = 47
2 x 16 = 32
2 x 7.5 = 15
32+15 = 47 = P
2007-02-08 15:57:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
p=2Ã16+2Ã7.5
p=32+15=47 km
2007-02-08 16:08:19 · answer #3 · answered by Luv Rulz 4 · 0⤊ 0⤋
P= 47 km (kilometers)
2W= 7.5kmx2= 15km
2L= 16km x 2 = 32km
15km+32km= 47km
That is how you get the answer if that is the length and width.
2007-02-08 16:03:48 · answer #4 · answered by Anonymous · 0⤊ 0⤋
perimeter is = to 47
method
2(16) + 2(7.5) =
32 + 15=
47
2007-02-08 16:00:15 · answer #5 · answered by iluvshusukefuji! 3 · 0⤊ 0⤋
47
2007-02-08 15:58:17 · answer #6 · answered by xeyaj 2 · 0⤊ 0⤋
p=2l+2w
p= 2(16) + 2(7.5)
p= 32 + 15
p= 47
47km
2007-02-08 16:03:57 · answer #7 · answered by . 3 · 0⤊ 0⤋
Just plug in, in the equation
P= 2L + 2W
=2(16)+2(7.5)
ans =47km
2007-02-08 16:02:44 · answer #8 · answered by Bee 1 · 0⤊ 0⤋
47 km
2007-02-08 16:13:56 · answer #9 · answered by Catholic 14 5 · 0⤊ 0⤋
here's how you do it:
Replace the variables (L and W) by the numbers you are given:
P=2(16)+2(7.5)
The ''2'' in front of the brackets means you must multiply what's in the brackets by 2, so:
P=32+15
Then add them:
P=47
2007-02-08 16:05:58 · answer #10 · answered by Anonymous · 0⤊ 0⤋
2*16+7.5*2
32+15
47
2007-02-08 16:18:39 · answer #11 · answered by Zaza 5 · 0⤊ 0⤋