H/W help!!! Biology?

Question

a rough coated male guinea pig is crossed with homozygous smooth coated female (rr). Their offspring are rough coated in 1:1 ratio. Use a punett square to calculate the genotype of the pale parent.

Answer 1

A punett square is a series of 4 (in this case) boxes.

Draw a square, then divide it into 4 boxes.
You know the mom is rr, so all she can give her offsping is r:
Put a small r on top of each of the two columns of the punet square and bring it down into the boxes.

In each of the boxes you now have an unknown.
You know the offspring get the dominant rough gene from the male parent, but what you are looking for is what HE adds to the mix. If he is RR, what will the offspring look like?
If he is Rr, what will the offspring look like?
He can't be rr, because you said he's rough.

a 1:1 proportion means that there are equal numbers of types of offspring. See if an RR or an Rr gives you the number- two different types in equal amounts.

Punett squares are wicked easy points on your next test. Take the time to learn to do one!

This article has pictures:
http://en.wikipedia.org/wiki/Punnett_square

Answer 2

Are you combining 2 questions here? You start out with rough and smooth, and end up asking about pale...Did you mean "male"?

If you really meant to determine the genotype of the rough male parent, you know that he had to have one dominant allele for roughness (R). Since he give offspring in this cross that are homozygous recessive (rr), the male parent HAD to have one recessive allele. So, he has to be heterozygous (Rr).

Answer 3

If you mean the genotype of the Rough parent, it would be Rr.

Answer 4

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Answer 5

alright i think i got your answer

http://www.sciforums.com/showthread.php?t=29157

:) hope it helps