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where must an object with a mass of 75 sq nuts be placed to balance a meter stick?

the other side of the meter has 200 square nuts placed 9 cm from the fulcrum.

2007-02-08 03:33:30 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

left torque = right torque

9 x 200 = X x 75

X=9 x 200/75 = 24 cm

2007-02-08 05:10:30 · answer #1 · answered by Edward 7 · 0⤊ 0⤋

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