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When a substrate that is catalyzed by an enzyme is present in high concentrations, the effect on the rate of a reaction by changeing the substrate concentration can be described using zeroth-order kinetics. If the concentration of a such a substrate is changed from 2.25 × 10−3 M to 4.12 × 10−1 M, by what factor does the rate of the reaction change ?



That is rate (4.12e-1M) = f × rate (2.25e-3M)

what is the vaule of f ?

2007-02-08 02:22:32 · 2 answers · asked by manutd11191988 1 in Science & Mathematics Chemistry

2 answers

1 because it is zeroth-order which the rates stay the same

2007-02-08 04:28:16 · answer #1 · answered by mei l 1 · 0 0

Rate is directly proportional.

2007-02-08 04:04:24 · answer #2 · answered by ag_iitkgp 7 · 0 0

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