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Question

2580 sweets were packed into bags of 80 and 70. The total no. of sweets packed into the bags of 80 was 620 more than the total no. of sweets into the bags of 70. How many bags of 70 sweets were there? (with working pls).

Thank you.

I tried this question but i cannot solve it myself...

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Answer 1

80x+70y=2580
80x=70y+620
Now substitute this into the top equation:
(70y+620)+70y=2580
140y+620=2580
140y=1960
y=14 70 count bags packed

Answer 2

Let x = the number of sweet bags packed with 80 pcs.
Let y = the number of sweet bags packed with 70 pcs.

Then we are told that x*80 = y*70 + 620 (Eq. 1)
The total candies in the 80-bags were 620 more (pcs of candy) that the total candies in all the 70-bags.

We also are told that x*80 + y*70 = 2580. (Eq. 2)
The total candies in both bags sum up to 2580.

We now have 2 equations in two unknowns.

80x -70y = 620 (notice i subtracted 70y from both sides of eq 1)
80x + 70y = 2580 (written as given). Since both these equations are equalities, the sums on the left side = the sums on the right side. Let's add them to get rid of the y term (since -70y+70y = 0)

We get 80x + 80x = 2580+620, or 160x = 3200 or x = 20.
that means the there are 20 bags of candy that contain 80 pcs each. All that remains is to find out how many bags have 70 pcs. Let's go back to the other equation...

80x - 70y = 620
80(20) - 70y = 620, or 70y = 980 (do the algebra yourself)
y then equals 14.

So to answer the question, there were 14 bags of candy that had 70 pcs. Check this by plugging the appropriate values into either equation, and you'll see they work.

Answer 3

If x is the number of bags of 80 and y is total number of bags then 80x = (y-x)70 + 620. Therefore, 150x - 70 y = 620

Also 80x + (y-x)70 = 2580. This gives 10x + 70y = 2580.

Solving these 2 equations gives, x = 20 and y = 34
Therefore, there are 14 bags of 70 sweets.

Answer 4

Use algebra to express the unknown numbers. You have x bags of 80 sweets and y bags of 70 sweets

x multiplied by 80 + y multiplied by 70 = 2580
x multiplied by 80 - y multiplied by 70 = 620

2580 + 620 = 3200

2 multiplied by x multiplied by 80 = 3200
x = 20

2580 - 620 = 1960

2 multiplied by y multiplied by 70 = 1960
y = 14

There were 14 bags of 70
(20 of 80)

Answer 5

There were 70 bags containing 14 sweets each bag. The 80 bags contained 20 sweets each.
70 x 14 = 980
80 x 20 =1600
total........2580

1600 minus 980 = 620

Just put that in algebraic form if you need to.

Answer 6

let us assume we have x bags of 80 sweets and y bags of 70 sweets

then the two equations formed are
x * 80 + y * 70 = 2580
x * 80 - y * 70 = 620

add the two equations together

2 * x * 80 = 3200
x = 20

subtract equation 2 from equation 1

2 * y * 70 = 1960
y = 14

So there were 14 bags of 70 sweets and 20 bags of 80 sweets

Answer 7

x = # of bags containing 80
y = # of bags containing 70

80x + 70y = 2580
and
80x = 620 + 70y

Take #2 and put it into #1:

(620 + 70y) + 70y = 2580
620 + 140y = 2580
140y = 1960
y = 14 bags of 70 sweets

Answer 8

Working

i)80a+70b=2580
ii)80a=70b+620
note: a=number of bags of 80 , b=number of bags of 70

use ii) in i)
(70b+620)+70b=2580
140b+620=2580
140b=1960
b=14

use ii) b replace by 14
80a=70(14)+620
80a=1600
a=20

Answer=14 bags of 70 sweets.