Functions...?

Question

I have to construct the graphic of this function:
y= rtsq (x^2 + 4x + 4) + rtsq (x^2 - 2x + 1)
As you can't draw the graphic, could you please solve this problem until it comes to the final point of the drawing?

Answer 1

The sqrt of (x^2 + 4x + 4) is | x+2 | ( modulus )
The sqrt of (x^2 - 2x + 1) is | x-1 |
so
y = (-x-2) + (-x + 1) = - 2x -1 when x < -2
y = (x+2) + (-x +1 ) = 3 when -2 <= x <= 1
y = (x+2) + ( x - 1 ) = 2x +1 when x > 1
where ( <= means less than or equal )
Now U can graph it

Answer 2

The sqrt of (x^2 + 4x + 4) is (x+2)
The sqrt of (x^2 - 2x + 1) is (x-1)

y = (x+2) + (x - 1)

y = 2x + 1

You will be graphing a line.

Answer 3

MamaMia has only got part of the answer

The square root of the first is +/-(x+2)
The square root of the second is +/-(x-1)

So you will be drawing

(x+2) + (x-1) = 2x+1
(x+2) - (x-1) = x + 3
-(x+2) + (x-1) = -(x+3)
-(x+2) - (x-1) = -(2x+1)

four straight lines!

Answer 4

Actually there are four graphs here.
x^2+4x+4 is nothing but squre of(x+2).
so rtsq(x^2+4x+4) is +(x+2) and-(x+2)
similarly rtsq (x^2 - 2x + 1) is +(x-1) and-(x-1).
there r 4 conditions now.
adding them y =2x+1,3,-3,-2x-1.