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plz tell me the formulae if through a object and measure the int. and final time of untill it strikes the ground from a building,can we calculate the hieght of the buliding?formulae?

2007-02-07 17:15:45 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

For a small solid object (rock, marble) the acceleration of gravity is 32 ft/sec/sec. That means you go 16 ft in the first second (0 to 32) 48 feet in the second second (32 to 64) and you can keep on going adding up the distances with time.
If you can measure it to a fraction of a second, then you have to integrate from 0 to the time 1/2*32t^2

2007-02-07 17:25:26 · answer #1 · answered by Mike1942f 7 · 0 0

Hold an object from top of the bldg and let it fall freely.Note the time taken by the object to hit the ground.Note this time as t

The height of the building can be calculated by the formulae
H=ut+1/2gt^2
where H =Ht of the building
u= Initial velocity of the object(0 in this case)
g=Acceleration due to gravity(9.8m/s^2)
Happy Computing

2007-02-08 01:53:43 · answer #2 · answered by sehjra 1 · 0 0

V (final) = V (initial) + acceleration * time

V initial is zero is starting from rest

acceleration = 9.8

then do can do this

V (final) squared = V (initial) squared + (2 *acceleration*distance)

then solve for distance

2007-02-08 10:57:22 · answer #3 · answered by Chuck Babu 1 · 0 0

h = 4.9 t^2

4.9 times the square of the time gives the height of the building.

2007-02-08 01:26:53 · answer #4 · answered by Pearlsawme 7 · 0 0

go to the top, hit your stopwatch, jumpoff, look at your stopwatch when you hit the bottom.

2007-02-08 01:23:10 · answer #5 · answered by thepizzadude 2 · 0 0

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