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2 answers

Let u=ln x, du=1/x dx. Then:

∫ln x/x dx = ∫u du = u²/2 + C = ln² x/2 + C

2007-02-07 16:32:17 · answer #1 · answered by Pascal 7 · 0 0

Int ln(x) /x dx If you put ln x= z you get 1/x *dx = dz.
Now you havle the Int z*dz = z^2/2 which is [ln(x)]^2 /2.
The way you wrote the answer is wrong

2007-02-08 07:25:44 · answer #2 · answered by santmann2002 7 · 0 0

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