Find an equation for the circle with diameter has endpoints at (-1,1) and (5,3)?

Answer 1

The center is the midpoint of the diameter, (2,2), and the radius is half the length of the diameter, which is √(6²+2²) = 2√10, so r = √10.

Then the equation is (x-2)² + (y-2)² = 10.

Answer 2

diameter has endpoints at (-1,1) and (5,3)
=>center at 2,2
radius = sqrt[(5-3)^2 + (3-1)^2]
= sqrt(10)
equation
(x-2)^2 + (y-2)^2 = 10