can u help me with this math problem? u have 2 show ur work and it has 2 be in general linear form ax+by=c?

Question

y=8/3x-5

Answer 1

All you're doing here is manipulating the equation so that it's in the more general form...

So let's do this - Let's subtract Y from both sides to get it on the same side with the X:
0=8/3x-y-5

Now, let's get that 5 over to the other side so it's got the C over there. So let's add 5 to both sides.

5=8/3x-y

And flip it 'round...
8/3x-y=5

A=8/3, B=-1, C=5

Orion

Answer 2

Sure! the general linear form of y=8/3x-5 is -8/3+y=-5. Where 8/3 is "ax" and "by" is 1y or y and -5 is "c".

Work:
y=8/3x-5
-8/3x -8/3x
-8/3x+y=-5

Best regards

Answer 3

Its very simple , you dont have to do much.
ur equation: y = 8/3x-5
Take the x factor on the L.H.S.and C on the R.H.S.
8/3x-y = 5
This is your ax+by=c form.
that gives A= 8/3, B= -1, C=5.

Answer 4

your problem is of the form y = mx + b
where m is the slope and b is the y - intercept.
your m = 8/3 and your b = -5
first: multiply all terms by 3
you have: 3y = 8x - 15
next: transposed 3y to the right side, and -15 to the left side
you have: 15 = 8x - 3y or 8x - 3y = 15.

Answer 5

add 5 to both sides ( it should cancel the 5 on your right side), then you need to subtract the y from both sides (so it can cancel the y on the left side) and you will end up with your answer!!!