Help me balance this equations?

0 ⤊

(NH4)2CO3 ==========> NH3 + H2O + CO2

2007-02-07 15:47:38 · 5 answers · asked by bambam4289 1 in Science & Mathematics ➔ Chemistry

2[(NH4)2CO3] -----> 4NH3 + 2H2O+ 2CO2

4 Nitrogens on each side
16 Hydrogens on each side
2 Carbons on each side
6 Oxygens on each side

Good luck!

2007-02-07 16:00:56 · answer #1 · answered by nhfox100 1 · 0⤊ 0⤋

(NH4)2CO3 ----> 2 NH3 + H2O + CO2

2007-02-07 23:51:59 · answer #2 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋

(NH4)2CO3 - (NH4)2CO3 = NH3 + H2O + CO2 - (NH3 + H2O + CO2)

2007-02-07 23:55:02 · answer #3 · answered by Astro newbie 3 · 0⤊ 1⤋

4(NH4)2CO3======>4NH3 + 2H2O +2CO2

2007-02-08 00:35:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋

Aww shucks! Somebody did it before I could!

2007-02-07 23:56:07 · answer #5 · answered by cutesy76 6 · 0⤊ 0⤋