x (first)
x+2 (second number 2 more than first)
x + (x+2) = 36
2x + 2 =36
2x = 34
x = 17
x+2 = 19
17 and 19
2007-02-07 15:23:32
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answer #1
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answered by aficionado210 2
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Let x be one of the numbers. Then, since one number is 2 more than the other, x + 2 is the other number.
The sum is 36, so
x + (x + 2) = 36
Solving this using basic algebra,
2x + 2 = 36
2x = 34
Therefore, x = 17
If we know that one number x is 17, then we can get the other number, x + 2 = 17 + 2 = 19.
So the two numbers are 17 and 19.
2007-02-07 15:24:03
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answer #2
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answered by Puggy 7
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17 and 19
2007-02-07 15:42:34
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answer #3
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answered by cutest pooky 3
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17 and 19
2007-02-07 15:28:32
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answer #4
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answered by Flutterburger 2
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17 and 19
2007-02-07 15:23:10
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answer #5
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answered by Paul BS 2
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the # are 19 & 17
2007-02-07 15:32:23
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answer #6
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answered by TED Z 1
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x + x+2 = 36
2x + 2 = 36
Subtract 2 from each side of the equation
2x = 34
2x/2 = 34/2
x = 17
1st # = 17
2nd # = 19
17+ 19 = 36
2007-02-07 15:29:44
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answer #7
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answered by maninthemirror327 3
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let the first number be N and the second number of course =
N +2
N + N + 2 = 36 =
2N +2 = 36
36-2= 2N = 34
34 into 2= 2n into 2= 1N = 17
First number = 17
Second number= 19 (17+2)
To check: 17+19=36!
2007-02-07 15:25:04
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answer #8
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answered by lemon drops 3
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x + (x + 2) = 36
2x = 36 - 2
x = 17, x + 2 = 19
the two numbers are 17 and 19
2007-02-07 15:23:33
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answer #9
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answered by mo b 4
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X+Y=36
X-Y=2 ADD
2X=38 DIVIDE BY 2
X=19
X-Y=2 SUBTRACT X FROM EACH SIDE
-Y=2-X SUBSTITUTE 19 FOR X
-Y=2-19=-17 DIVIDE BOTH SIDES BY -1
Y=17
THE NUMBERS ARE 17 & 19
2007-02-08 04:12:36
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answer #10
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answered by yupchagee 7
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