You are on roller blades on top of a large hill. Your potential energy is equal to 1000 joules. You weigh 60kg (588N). If you start skating down this hill, your potential energy will be converted to kinetic energy. At the bottom of the hill, your kinetic energy will be equal to your potential energy at the top.
What will be your speed at the bottom of the hill?
I really don't understand this. Please help.
2007-02-07 15:13:33 · 5 answers · asked by Jewel 2 in Science & Mathematics ➔ Physics
according to principle of conservation of energry ur total potential enrgy will be changed in to kinetic energy, neglecting the energy losses and assuming no physical work is done during skatting ie you skate freely.
kinetic energy of a body is given by m* v^2 /2, where m is the mass and Velocity. u know total kinetic energy and the mass so it is a matter of substituting.
2007-02-07 15:23:05 · answer #1 · answered by san 3 · 0⤊ 0⤋
mgh=1/2 m v^2 ==> 1000=1/2 * 60 * v^2 ===>v^2=100/3===>v=10/(3^1/2)
if we don't have friction the first energy is same as final energy!
2007-02-08 02:19:41 · answer #2 · answered by shiva 3 · 0⤊ 0⤋
since potential energy is transferred to kinetic energy, they are equal
PE = KE
expand KE, you don't have to expand PE because they already gave it to you.
PE = 1/2mv^2
now just plug in chunks
1000J = 1/2(60kg)v^2
just solve for v
2007-02-07 23:21:55 · answer #3 · answered by 7 · 0⤊ 0⤋
ke=1000
1/2mv^2=1000
2007-02-07 23:22:18 · answer #4 · answered by tarundeep300 3 · 0⤊ 0⤋
sure y not
2007-02-07 23:16:58 · answer #5 · answered by Anonymous · 0⤊ 1⤋