the sum of two numbers is 28, and their diffrence is 4. what are the numbers.?

Question

please show how you got it

Answer 1

Set the smaller number as x, and the other will be x + 4.

x + (x + 4) = 28
2x + 4 = 28
2x = 24
x = 12; thus x + 4 = 16

Answer 2

my answer sure wasn't new math. i took 1/2 of 28 =14 and then took 1 away from 14 to make it 13 and added 1 to the other 14 to make it 15 i did this until i got 4 in between the numbers and then added them together to get 12+16 =28. I don't think this was the way you are to do this but that's how i did. the difference between 12 and 16 is 4.

Answer 3

a - b = 4
Substitute a in terms of b: a = 4 + b

Then, plug this substitution back into the other equation:
a + b = 28
(4 + b) + b = 28
4 + 2b = 28
2b = 28 - 4
2b = 24
b = 12

Since a = 4 + b, then plugging in b = 12 into this equation results in: a = 4 + (12)
a = 16

Answer 4

12 and 16. I divided 28 in half, got 14, then subtracted 2 from 14 to get 12, and added 2 to 14 to get 16. thus giving a difference of 4.

Answer 5

it is the form you do it. First, upload the numbers. 28+4 = 32. Then, divide the numbers by 2. 32/2 = sixteen. that's one type. next, subtract the version from the variety you found. sixteen-4 = 12. The numbers are 12 and sixteen.

Answer 6

12 & 16
14+14=28 then by trial and error work on the difference of 4 to total 28

Answer 7

Let the numbers be x and y.

Since their sum is 28, x+y=28.
Since their difference is 4, x-y=4

To solve the equations, you can add the two together to get:

2x=32
x=16

Then plug x back in to find y:

16+y=28
y=12

So the numbers are 12 and 16.

Answer 8

x+y=28
x-4=y

take first equation and solve for y:
y=28-x
now plug 28-x into the second equation where the "y' is:

x-4=28-x
2x=32
x=16

y=28-x, so y=28-16=12

check:
16+12=28 and 16 and 12 have a difference of 4... so it works

Answer 9

12 & 16

Answer 10

16 and 12 add them together you get 28 subtract the two and you get 4.