Could some one help me with Physics: The cooling system of a car's engine holds 20.0 L of water. (1L=1kg)?

Question

What is the change in the (liquid) water's temperature if the engine operates until 836000 J of Heat are added?

And the specific heat of water is 4.18

But i don't know how to plug it in.

Answer 1

You can get a clue how to proceed by looknig at the units of specific heat. You didn't mention the units, but for water, Cp = 4.187 J/(gm K)

So, you know the mass of the water (20 kg = 20 000 gm).
You know how much heat was added (836 000 J)

Even if yiou can't remember the formula directly, the units of the specific heat tell you what to do: each 4.18 J of heat produces a rise of 1 K in 1 gm of water.
So 836 000 J into 20 000 gm of water produces a rise of?

Answer 2

836000 X 0.0002389 / 20 = ~10 C. that's assuming that each and each body the added warmth is going purely into the water, none has been dissipated by technique of the radiator or via the engine block and none has been switched over to artwork.

Answer 3

wikipedia is a good place to search for articles about things like this. I have included a link to an article on Specific heat.