Need help with this physics problem: The cooling system of a car's engine holds 20.0 L of water. (1L=1kg)?

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Need help with this physics problem: The cooling system of a car's engine holds 20.0 L of water. (1L=1kg)?

What is the change in the (liquid) water's temperature if the engine operates until 836000 J of Heat are added? I don't know the formulas need help.

2007-02-07 14:32:16 · 2 answers · asked by Eric 1 in Science & Mathematics ➔ Physics

2 answers

Already answered the LAST time you asked the question... go there.

2007-02-07 14:35:11 · answer #1 · answered by Dangermouse! 2 · 0⤊ 0⤋

836000 X 0.0002389 / 20 = ~10 C.
This is assuming that all the added heat is going only into the water, none has been dissipated by the radiator or through the engine block and none has been converted to work.

2007-02-07 23:02:24 · answer #2 · answered by Bomba 7 · 0⤊ 0⤋